Soru: Fe³⁺/Fe²⁺ yarı hücresinde [Fe³⁺] = 0.1 M ve [Fe²⁺] = 0.01 M ise elektrot potansiyelini bulun. E°(Fe³⁺/Fe²⁺) = +0.77 V, 25°C.
Çözüm: Nernst denklemi: E = E° - (0.059/n) * log([Fe²⁺]/[Fe³⁺]). Reaksiyon: Fe³⁺ + e⁻ → Fe²⁺, n = 1. E = 0.77 - (0.059/1) * log(0.01/0.1) = 0.77 - 0.059 * log(0.1) = 0.77 - 0.059 * (-1) = 0.77 + 0.059 = 0.829 V.
